Optimal. Leaf size=116 \[ \frac{1}{4} c^4 \left (a+b \tan ^{-1}(c x)\right )^2+\frac{b c^3 \left (a+b \tan ^{-1}(c x)\right )}{2 x}-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}-\frac{b^2 c^2}{12 x^2}+\frac{1}{3} b^2 c^4 \log \left (c^2 x^2+1\right )-\frac{2}{3} b^2 c^4 \log (x) \]
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Rubi [A] time = 0.218944, antiderivative size = 116, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.571, Rules used = {4852, 4918, 266, 44, 36, 29, 31, 4884} \[ \frac{1}{4} c^4 \left (a+b \tan ^{-1}(c x)\right )^2+\frac{b c^3 \left (a+b \tan ^{-1}(c x)\right )}{2 x}-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}-\frac{b^2 c^2}{12 x^2}+\frac{1}{3} b^2 c^4 \log \left (c^2 x^2+1\right )-\frac{2}{3} b^2 c^4 \log (x) \]
Antiderivative was successfully verified.
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Rule 4852
Rule 4918
Rule 266
Rule 44
Rule 36
Rule 29
Rule 31
Rule 4884
Rubi steps
\begin{align*} \int \frac{\left (a+b \tan ^{-1}(c x)\right )^2}{x^5} \, dx &=-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}+\frac{1}{2} (b c) \int \frac{a+b \tan ^{-1}(c x)}{x^4 \left (1+c^2 x^2\right )} \, dx\\ &=-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}+\frac{1}{2} (b c) \int \frac{a+b \tan ^{-1}(c x)}{x^4} \, dx-\frac{1}{2} \left (b c^3\right ) \int \frac{a+b \tan ^{-1}(c x)}{x^2 \left (1+c^2 x^2\right )} \, dx\\ &=-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}+\frac{1}{6} \left (b^2 c^2\right ) \int \frac{1}{x^3 \left (1+c^2 x^2\right )} \, dx-\frac{1}{2} \left (b c^3\right ) \int \frac{a+b \tan ^{-1}(c x)}{x^2} \, dx+\frac{1}{2} \left (b c^5\right ) \int \frac{a+b \tan ^{-1}(c x)}{1+c^2 x^2} \, dx\\ &=-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}+\frac{b c^3 \left (a+b \tan ^{-1}(c x)\right )}{2 x}+\frac{1}{4} c^4 \left (a+b \tan ^{-1}(c x)\right )^2-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}+\frac{1}{12} \left (b^2 c^2\right ) \operatorname{Subst}\left (\int \frac{1}{x^2 \left (1+c^2 x\right )} \, dx,x,x^2\right )-\frac{1}{2} \left (b^2 c^4\right ) \int \frac{1}{x \left (1+c^2 x^2\right )} \, dx\\ &=-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}+\frac{b c^3 \left (a+b \tan ^{-1}(c x)\right )}{2 x}+\frac{1}{4} c^4 \left (a+b \tan ^{-1}(c x)\right )^2-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}+\frac{1}{12} \left (b^2 c^2\right ) \operatorname{Subst}\left (\int \left (\frac{1}{x^2}-\frac{c^2}{x}+\frac{c^4}{1+c^2 x}\right ) \, dx,x,x^2\right )-\frac{1}{4} \left (b^2 c^4\right ) \operatorname{Subst}\left (\int \frac{1}{x \left (1+c^2 x\right )} \, dx,x,x^2\right )\\ &=-\frac{b^2 c^2}{12 x^2}-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}+\frac{b c^3 \left (a+b \tan ^{-1}(c x)\right )}{2 x}+\frac{1}{4} c^4 \left (a+b \tan ^{-1}(c x)\right )^2-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}-\frac{1}{6} b^2 c^4 \log (x)+\frac{1}{12} b^2 c^4 \log \left (1+c^2 x^2\right )-\frac{1}{4} \left (b^2 c^4\right ) \operatorname{Subst}\left (\int \frac{1}{x} \, dx,x,x^2\right )+\frac{1}{4} \left (b^2 c^6\right ) \operatorname{Subst}\left (\int \frac{1}{1+c^2 x} \, dx,x,x^2\right )\\ &=-\frac{b^2 c^2}{12 x^2}-\frac{b c \left (a+b \tan ^{-1}(c x)\right )}{6 x^3}+\frac{b c^3 \left (a+b \tan ^{-1}(c x)\right )}{2 x}+\frac{1}{4} c^4 \left (a+b \tan ^{-1}(c x)\right )^2-\frac{\left (a+b \tan ^{-1}(c x)\right )^2}{4 x^4}-\frac{2}{3} b^2 c^4 \log (x)+\frac{1}{3} b^2 c^4 \log \left (1+c^2 x^2\right )\\ \end{align*}
Mathematica [A] time = 0.0875461, size = 128, normalized size = 1.1 \[ \frac{-3 a^2+6 a b c^3 x^3+2 b \tan ^{-1}(c x) \left (3 a \left (c^4 x^4-1\right )+b c x \left (3 c^2 x^2-1\right )\right )-2 a b c x-b^2 c^2 x^2-8 b^2 c^4 x^4 \log (x)+4 b^2 c^4 x^4 \log \left (c^2 x^2+1\right )+3 b^2 \left (c^4 x^4-1\right ) \tan ^{-1}(c x)^2}{12 x^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.017, size = 147, normalized size = 1.3 \begin{align*} -{\frac{{a}^{2}}{4\,{x}^{4}}}-{\frac{{b}^{2} \left ( \arctan \left ( cx \right ) \right ) ^{2}}{4\,{x}^{4}}}+{\frac{{c}^{4}{b}^{2} \left ( \arctan \left ( cx \right ) \right ) ^{2}}{4}}-{\frac{c{b}^{2}\arctan \left ( cx \right ) }{6\,{x}^{3}}}+{\frac{{b}^{2}{c}^{3}\arctan \left ( cx \right ) }{2\,x}}+{\frac{{b}^{2}{c}^{4}\ln \left ({c}^{2}{x}^{2}+1 \right ) }{3}}-{\frac{{b}^{2}{c}^{2}}{12\,{x}^{2}}}-{\frac{2\,{c}^{4}{b}^{2}\ln \left ( cx \right ) }{3}}-{\frac{ab\arctan \left ( cx \right ) }{2\,{x}^{4}}}+{\frac{{c}^{4}ab\arctan \left ( cx \right ) }{2}}-{\frac{abc}{6\,{x}^{3}}}+{\frac{a{c}^{3}b}{2\,x}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.53828, size = 205, normalized size = 1.77 \begin{align*} \frac{1}{6} \,{\left ({\left (3 \, c^{3} \arctan \left (c x\right ) + \frac{3 \, c^{2} x^{2} - 1}{x^{3}}\right )} c - \frac{3 \, \arctan \left (c x\right )}{x^{4}}\right )} a b + \frac{1}{12} \,{\left (2 \,{\left (3 \, c^{3} \arctan \left (c x\right ) + \frac{3 \, c^{2} x^{2} - 1}{x^{3}}\right )} c \arctan \left (c x\right ) - \frac{{\left (3 \, c^{2} x^{2} \arctan \left (c x\right )^{2} - 4 \, c^{2} x^{2} \log \left (c^{2} x^{2} + 1\right ) + 8 \, c^{2} x^{2} \log \left (x\right ) + 1\right )} c^{2}}{x^{2}}\right )} b^{2} - \frac{b^{2} \arctan \left (c x\right )^{2}}{4 \, x^{4}} - \frac{a^{2}}{4 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.75023, size = 297, normalized size = 2.56 \begin{align*} \frac{4 \, b^{2} c^{4} x^{4} \log \left (c^{2} x^{2} + 1\right ) - 8 \, b^{2} c^{4} x^{4} \log \left (x\right ) + 6 \, a b c^{3} x^{3} - b^{2} c^{2} x^{2} - 2 \, a b c x + 3 \,{\left (b^{2} c^{4} x^{4} - b^{2}\right )} \arctan \left (c x\right )^{2} - 3 \, a^{2} + 2 \,{\left (3 \, a b c^{4} x^{4} + 3 \, b^{2} c^{3} x^{3} - b^{2} c x - 3 \, a b\right )} \arctan \left (c x\right )}{12 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.6149, size = 170, normalized size = 1.47 \begin{align*} \begin{cases} - \frac{a^{2}}{4 x^{4}} + \frac{a b c^{4} \operatorname{atan}{\left (c x \right )}}{2} + \frac{a b c^{3}}{2 x} - \frac{a b c}{6 x^{3}} - \frac{a b \operatorname{atan}{\left (c x \right )}}{2 x^{4}} - \frac{2 b^{2} c^{4} \log{\left (x \right )}}{3} + \frac{b^{2} c^{4} \log{\left (x^{2} + \frac{1}{c^{2}} \right )}}{3} + \frac{b^{2} c^{4} \operatorname{atan}^{2}{\left (c x \right )}}{4} + \frac{b^{2} c^{3} \operatorname{atan}{\left (c x \right )}}{2 x} - \frac{b^{2} c^{2}}{12 x^{2}} - \frac{b^{2} c \operatorname{atan}{\left (c x \right )}}{6 x^{3}} - \frac{b^{2} \operatorname{atan}^{2}{\left (c x \right )}}{4 x^{4}} & \text{for}\: c \neq 0 \\- \frac{a^{2}}{4 x^{4}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \arctan \left (c x\right ) + a\right )}^{2}}{x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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